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Balancing radiant floor loops: the gpm of every loop from the room's heat loss - 11 loops worked through

Balancing radiant floor loops step by step: from a room's heat loss to the flow meter setting. In a 1,100 ft² house at 104/95 °F the loops need 0.16 to 0.36 gpm.

Founder of HeatAlgo, author of the calculation engine to EN 12831 and EN 1264

Short answer: balancing radiant floor loops means setting each loop on the manifold to the flow its design gives it, not one gpm for all of them. A loop's flow follows from the room's heat loss in four steps: the room's heat loss, the heat the water carries, the temperature drop in the loop, and gpm = Btu/h ÷ (500 × ΔT °F). In the HeatAlgo reference house - 1,100 ft², a -4 °F design day, PEX at 6 in on center, 104/95 °F water - the eleven loops need from 0.16 gpm in the bathroom to 0.36 gpm in the hall, 2.65 gpm in total.

The article what radiant floor flow meters should read shows that every loop needs a different flow. Here we work out where each of those numbers comes from: from the room's heat loss to what the flow meter should read. Every figure was calculated by HeatAlgo's radiant floor module (EN 1264-2 and EN 1264-3) for the reference house: tile in the kitchen, bathroom, hall and mechanical room, engineered wood in the other rooms, 16 mm PEX, 1.8 in of cement screed over the tubing, loops laid at 6 in on center across the whole floor.

Balancing radiant floor loops in four steps: the hall

The hall has 110 ft² of tile floor and one loop. This is how its setting comes about:

  1. The room's heat loss. The heat loss calculation gives the hall 1,887 Btu/h. That is the heat the floor has to put into the room.
  2. The heat the water carries. The water also loses heat downward, through the insulation under the tubing. EN 1264-3 (Formula 13) therefore adds the floor's own heat loss from the calculation again under the tubing, 375 Btu/h in the hall, and multiplies the sum by 1 + Ro/Ru - the ratio of the thermal resistance above the tubing to the one below it. In the hall that is 4.5% more: 2,363 Btu/h in the water.
  3. The temperature drop in the loop. The manifold gives one supply water temperature. The mechanical room (61 °F, 22.1 Btu/h·ft²) needs 102.8 °F, so the module sets 104 °F for the whole house. The hall manages with 101.7 °F, so its loop may cool the water by more than the design 9 °F: the water comes back from the hall at 90.9 °F, a 13.1 °F drop.
  4. The flow. 2,363 Btu/h ÷ (500 × 13.1 °F) = 0.36 gpm. That is what the hall loop's flow meter should read.

The gpm of every loop: what the flow meters should read

The same sum for all eleven loops with 104/95 °F water. Where a room has several loops, its heat loss is shared equally, because the loops have the same area and flooring.

LoopHeat lossFloor's own loss, again underneathHeat in the waterTemperature dropFlow meter
Living room, each of 3 loops (wood)1,524 Btu/h350 Btu/h1,967 Btu/h15.5 °F0.25 gpm
Kitchen (tile)1,298 Btu/h379 Btu/h1,755 Btu/h18 °F0.19 gpm
Bedroom, each of 2 loops (wood)1,285 Btu/h324 Btu/h1,696 Btu/h16.5 °F0.21 gpm
Room 1 and Room 2, 1 loop each (wood)1,534 Btu/h423 Btu/h2,049 Btu/h18 °F0.23 gpm
Bathroom, 75 °F (tile)1,062 Btu/h338 Btu/h1,450 Btu/h18 °F0.16 gpm
Hall (tile)1,887 Btu/h375 Btu/h2,363 Btu/h13.1 °F0.36 gpm
Mechanical room, 61 °F (tile)1,428 Btu/h235 Btu/h1,752 Btu/h11.3 °F0.31 gpm

Together the eleven loops need 2.65 gpm through the manifold. The hall gets the most water - it loses the most heat per square foot of the rooms heated to 68 °F, and its water cools less than in the other rooms. The bathroom gets the least. The kitchen, both rooms and the bathroom have an 18 °F drop - the most HeatAlgo's module allows for one loop.

No loop here runs at the design 9 °F drop. Set the supply water to exactly 102.8 °F and the mechanical room loop would drop 9 °F, and every other setting would move. That is why the flow meter table is worked out for the water temperature the house actually runs at.

Why not the same gpm on every loop

Eleven loops at 0.40 gpm make 4.40 gpm - 66% more than this house needs. The bathroom loop would get 2.5 times the water the design gives it, and its water would come back warmer. The circulator has to move all of that water, and the hall, which needs the water most, gets no more of it. What happens to the hall when its flow meter reads too little is in radiant floor heating not heating one room.

How to set the flow meters on the manifold

  1. Run the system at the design supply water temperature and open every actuator (thermostats turned all the way up).
  2. Set each flow meter to its loop's gpm from the table.
  3. Go along the manifold a second time. Turning one loop down sends more water to the others, so the first settings move.
  4. Check the total. The flow meters together should give the manifold's flow, here 2.65 gpm. If a loop cannot reach its figure even with its flow meter fully open, the circulator gives too little or the loop's resistance is too high - that is one for your installer.

What the table does not tell you

The design flow is the value to set on the flow meter. HeatAlgo's module also gives each loop's pressure drop, but it does not work out valve presettings or size the circulator. These are calculations, not measurements, for the reference house with hydronic radiant floor heating in a screed, to EN 1264 - not to any US design manual. Your house will give different numbers - the same steps, the same formula.

Work out the flow meter table for your own house

In HeatAlgo's radiant floor heating design tool every loop gets its heat, its temperature drop and its flow from the same four steps, and the Flow meters table lists them by manifold and port - ready to set on site. A free account shows the full result for one loop; the report gives the table for every loop.

Work out the flow of every loop

A HeatAlgo report follows EN 12831-1 and EN 1264, not ACCA Manual J, and is not accepted for permits or rebates.

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FAQ

Frequently asked questions

What does balancing radiant floor loops mean?

Setting each loop on the manifold to the flow its design gives it: gpm = Btu/h ÷ (500 × ΔT °F), where Btu/h is the heat the water in the loop carries and ΔT is how much the water cools in the loop. In the HeatAlgo reference house with 104/95 °F water, the eleven loops need 0.16 gpm (bathroom) to 0.36 gpm (hall), 2.65 gpm in total.

How do I set the flow meters on a radiant floor manifold?

With the system running and every actuator open, set each flow meter to its loop's figure from the table, then go along the manifold a second time, because changing one loop shifts the others. The flow meters should add up to the manifold's total flow - 2.65 gpm in the HeatAlgo reference house.

Can I set every radiant floor loop to the same gpm?

You can, but that is not balancing. In the HeatAlgo reference house 11 loops at 0.40 gpm make 4.40 gpm, 66% more than the 2.65 gpm the design needs, and the bathroom loop would get 2.5 times the water it needs.

Why do the loops in one house have different temperature drops?

Because the manifold gives every loop one supply water temperature, set by the hardest room. In the HeatAlgo reference house that is the mechanical room, which needs 102.8 °F. Rooms that manage with cooler water cool it further: the hall by 13.1 °F, the kitchen, rooms 1 and 2 and the bathroom by 18 °F, so they need less water.

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